The average number of starfruits in Container F, Container G and Container H is 22 and it is 4 more than the average number of pears in the 3 containers.
19 of the pears are in Container F and the pears in Container F is 30% of the number of pears in Container G. If each container has the same number of fruits, what percentage of the fruits in Container H are starfruits?
Average number of pears
= 22 - 4
= 18
Total number of pears
= 3 x 18
= 54
Total number of starfruits
= 3 x 22
= 66
Total number of fruits
= 54 + 66
= 120
Number of fruits in each container
= 120 ÷ 3
= 40
Pears in Container F |
Pears in Container G |
Pears in Container H |
Total pears |
1x3 |
8x3 |
9x3 |
3x1 |
10x1 |
|
|
3 u |
10 u |
14 u |
27 u |
30% =
30100 =
310The number of pears in Container F is repeated. Make the number of pears in Container F the same. LCM of 1 and 3 is 3.
Total number of pears
= 3 u + 10 u + 14 u
= 27 u
27 u = 54
1 u = 54 ÷ 27 = 2
Number of pears in Container H
= 14 u
= 14 x 2
= 28
Number of starfruits in Container H
= 40 - 28
= 12
Percentage of the fruits in Container H are starfruits
=
1240 x 100%
= 30%
Answer(s): 30%