The average number of pears in Box M, Box N and Box P is 51 and it is 2 more than the average number of pomegranates in the 3 boxes. ¹₇ of the pomegranates are in Box M and the pomegranates in Box M is 60% of the number of pomegranates in Box N. If each box has the same number of fruits, what percentage of the fruits in Box P are pears?
Average number of pomegranates
= 51 - 2
= 49

Total number of pomegranates
= 3 x 49
= 147

Total number of pears
= 3 x 51 
= 153

Total number of fruits
= 147 + 153
= 300

Number of fruits in each box
= 300 ÷ 3
= 100

Pomegranates in Box M	Pomegranates in Box N	Pomegranates in Box P	Total pomegranates
1x3	6x3		7x3
3x1	5x1
3 u	5 u	13 u	21 u

60% = ⁶⁰₁₀₀ = ³₅

The number of pomegranates in Box M is repeated.  Make the number of pomegranates in Box M the same.  LCM of 1 and 3 is 3. 

Total number of pomegranates
= 3 u + 5 u + 13 u
= 21 u

21 u = 147

1 u = 147 ÷ 21 = 7

Number of pomegranates in Box P
= 13 u
= 13 x 7
= 91

Number of pears in Box P
= 100 - 91
= 9

Percentage of the fruits in Box P are pears
= ⁹₁₀₀ x 100%
= 9%

Answer(s): 9%