The average number of kiwis in Box X, Box Y and Box Z is 29 and it is 2 more than the average number of persimmons in the 3 boxes. ¹₉ of the persimmons are in Box X and the persimmons in Box X is 30% of the number of persimmons in Box Y. If each box has the same number of fruits, what percentage of the fruits in Box Z are kiwis?
Average number of persimmons
= 29 - 2
= 27

Total number of persimmons
= 3 x 27
= 81

Total number of kiwis
= 3 x 29 
= 87

Total number of fruits
= 81 + 87
= 168

Number of fruits in each box
= 168 ÷ 3
= 56

Persimmons in Box X	Persimmons in Box Y	Persimmons in Box Z	Total persimmons
1x3	8x3		9x3
3x1	10x1
3 u	10 u	14 u	27 u

30% = ³⁰₁₀₀ = ³₁₀

The number of persimmons in Box X is repeated.  Make the number of persimmons in Box X the same.  LCM of 1 and 3 is 3. 

Total number of persimmons
= 3 u + 10 u + 14 u
= 27 u

27 u = 81

1 u = 81 ÷ 27 = 3

Number of persimmons in Box Z
= 14 u
= 14 x 3
= 42

Number of kiwis in Box Z
= 56 - 42
= 14

Percentage of the fruits in Box Z are kiwis
= ¹⁴₅₆ x 100%
= 25%

Answer(s): 25%