The average number of pears in Container V, Container W and Container X is 31 and it is 7 more than the average number of pomegranates in the 3 containers.
19 of the pomegranates are in Container V and the pomegranates in Container V is 40% of the number of pomegranates in Container W. If each container has the same number of fruits, what percentage of the fruits in Container X are pears?
Average number of pomegranates
= 31 - 7
= 24
Total number of pomegranates
= 3 x 24
= 72
Total number of pears
= 3 x 31
= 93
Total number of fruits
= 72 + 93
= 165
Number of fruits in each container
= 165 ÷ 3
= 55
Pomegranates in Container V |
Pomegranates in Container W |
Pomegranates in Container X |
Total pomegranates |
1x2 |
8x2 |
9x2 |
2x1 |
5x1 |
|
|
2 u |
5 u |
11 u |
18 u |
40% =
40100 =
25The number of pomegranates in Container V is repeated. Make the number of pomegranates in Container V the same. LCM of 1 and 2 is 2.
Total number of pomegranates
= 2 u + 5 u + 11 u
= 18 u
18 u = 72
1 u = 72 ÷ 18 = 4
Number of pomegranates in Container X
= 11 u
= 11 x 4
= 44
Number of pears in Container X
= 55 - 44
= 11
Percentage of the fruits in Container X are pears
=
1155 x 100%
= 20%
Answer(s): 20%