The average number of pears in Box X, Box Y and Box Z is 25 and it is 10 more than the average number of oranges in the 3 boxes. ¹₅ of the oranges are in Box X and the oranges in Box X is 60% of the number of oranges in Box Y. If each box has the same number of fruits, what percentage of the fruits in Box Z are pears?
Average number of oranges
= 25 - 10
= 15

Total number of oranges
= 3 x 15
= 45

Total number of pears
= 3 x 25 
= 75

Total number of fruits
= 45 + 75
= 120

Number of fruits in each box
= 120 ÷ 3
= 40

Oranges in Box X	Oranges in Box Y	Oranges in Box Z	Total oranges
1x3	4x3		5x3
3x1	5x1
3 u	5 u	7 u	15 u

60% = ⁶⁰₁₀₀ = ³₅

The number of oranges in Box X is repeated.  Make the number of oranges in Box X the same.  LCM of 1 and 3 is 3. 

Total number of oranges
= 3 u + 5 u + 7 u
= 15 u

15 u = 45

1 u = 45 ÷ 15 = 3

Number of oranges in Box Z
= 7 u
= 7 x 3
= 21

Number of pears in Box Z
= 40 - 21
= 19

Percentage of the fruits in Box Z are pears
= ¹⁹₄₀ x 100%
= 47.5%

Answer(s): 47.5%