The average number of pomegranates in Container Q, Container R and Container S is 55 and it is 6 more than the average number of kiwis in the 3 containers.
17 of the kiwis are in Container Q and the kiwis in Container Q is 60% of the number of kiwis in Container R. If each container has the same number of fruits, what percentage of the fruits in Container S are pomegranates?
Average number of kiwis
= 55 - 6
= 49
Total number of kiwis
= 3 x 49
= 147
Total number of pomegranates
= 3 x 55
= 165
Total number of fruits
= 147 + 165
= 312
Number of fruits in each container
= 312 ÷ 3
= 104
Kiwis in Container Q |
Kiwis in Container R |
Kiwis in Container S |
Total kiwis |
1x3 |
6x3 |
7x3 |
3x1 |
5x1 |
|
|
3 u |
5 u |
13 u |
21 u |
60% =
60100 =
35The number of kiwis in Container Q is repeated. Make the number of kiwis in Container Q the same. LCM of 1 and 3 is 3.
Total number of kiwis
= 3 u + 5 u + 13 u
= 21 u
21 u = 147
1 u = 147 ÷ 21 = 7
Number of kiwis in Container S
= 13 u
= 13 x 7
= 91
Number of pomegranates in Container S
= 104 - 91
= 13
Percentage of the fruits in Container S are pomegranates
=
13104 x 100%
= 12.5%
Answer(s): 12.5%