The average number of pears in Container V, Container W and Container X is 18 and it is 4 more than the average number of persimmons in the 3 containers.
17 of the persimmons are in Container V and the persimmons in Container V is 30% of the number of persimmons in Container W. If each container has the same number of fruits, what percentage of the fruits in Container X are pears?
Average number of persimmons
= 18 - 4
= 14
Total number of persimmons
= 3 x 14
= 42
Total number of pears
= 3 x 18
= 54
Total number of fruits
= 42 + 54
= 96
Number of fruits in each container
= 96 ÷ 3
= 32
Persimmons in Container V |
Persimmons in Container W |
Persimmons in Container X |
Total persimmons |
1x3 |
6x3 |
7x3 |
3x1 |
10x1 |
|
|
3 u |
10 u |
8 u |
21 u |
30% =
30100 =
310The number of persimmons in Container V is repeated. Make the number of persimmons in Container V the same. LCM of 1 and 3 is 3.
Total number of persimmons
= 3 u + 10 u + 8 u
= 21 u
21 u = 42
1 u = 42 ÷ 21 = 2
Number of persimmons in Container X
= 8 u
= 8 x 2
= 16
Number of pears in Container X
= 32 - 16
= 16
Percentage of the fruits in Container X are pears
=
1632 x 100%
= 50%
Answer(s): 50%