The average number of pears in Container A, Container B and Container C is 65 and it is 2 more than the average number of starfruits in the 3 containers. ¹₇ of the starfruits are in Container A and the starfruits in Container A is 30% of the number of starfruits in Container B. If each container has the same number of fruits, what percentage of the fruits in Container C are pears?
Average number of starfruits
= 65 - 2
= 63

Total number of starfruits
= 3 x 63
= 189

Total number of pears
= 3 x 65 
= 195

Total number of fruits
= 189 + 195
= 384

Number of fruits in each container
= 384 ÷ 3
= 128

Starfruits in Container A	Starfruits in Container B	Starfruits in Container C	Total starfruits
1x3	6x3		7x3
3x1	10x1
3 u	10 u	8 u	21 u

30% = ³⁰₁₀₀ = ³₁₀

The number of starfruits in Container A is repeated.  Make the number of starfruits in Container A the same.  LCM of 1 and 3 is 3. 

Total number of starfruits
= 3 u + 10 u + 8 u
= 21 u

21 u = 189

1 u = 189 ÷ 21 = 9

Number of starfruits in Container C
= 8 u
= 8 x 9
= 72

Number of pears in Container C
= 128 - 72
= 56

Percentage of the fruits in Container C are pears
= ⁵⁶₁₂₈ x 100%
= 43.75%

Answer(s): 43.75%