The average number of kiwis in Container K, Container L and Container M is 20 and it is 8 more than the average number of pomegranates in the 3 containers.
16 of the pomegranates are in Container K and the pomegranates in Container K is 30% of the number of pomegranates in Container L. If each container has the same number of fruits, what percentage of the fruits in Container M are kiwis?
Average number of pomegranates
= 20 - 8
= 12
Total number of pomegranates
= 3 x 12
= 36
Total number of kiwis
= 3 x 20
= 60
Total number of fruits
= 36 + 60
= 96
Number of fruits in each container
= 96 ÷ 3
= 32
Pomegranates in Container K |
Pomegranates in Container L |
Pomegranates in Container M |
Total pomegranates |
1x3 |
5x3 |
6x3 |
3x1 |
10x1 |
|
|
3 u |
10 u |
5 u |
18 u |
30% =
30100 =
310The number of pomegranates in Container K is repeated. Make the number of pomegranates in Container K the same. LCM of 1 and 3 is 3.
Total number of pomegranates
= 3 u + 10 u + 5 u
= 18 u
18 u = 36
1 u = 36 ÷ 18 = 2
Number of pomegranates in Container M
= 5 u
= 5 x 2
= 10
Number of kiwis in Container M
= 32 - 10
= 22
Percentage of the fruits in Container M are kiwis
=
2232 x 100%
= 68.75%
Answer(s): 68.75%