The average number of starfruits in Container D, Container E and Container F is 20 and it is 8 more than the average number of apples in the 3 containers.
16 of the apples are in Container D and the apples in Container D is 60% of the number of apples in Container E. If each container has the same number of fruits, what percentage of the fruits in Container F are starfruits?
Average number of apples
= 20 - 8
= 12
Total number of apples
= 3 x 12
= 36
Total number of starfruits
= 3 x 20
= 60
Total number of fruits
= 36 + 60
= 96
Number of fruits in each container
= 96 ÷ 3
= 32
Apples in Container D |
Apples in Container E |
Apples in Container F |
Total apples |
1x3 |
5x3 |
6x3 |
3x1 |
5x1 |
|
|
3 u |
5 u |
10 u |
18 u |
60% =
60100 =
35The number of apples in Container D is repeated. Make the number of apples in Container D the same. LCM of 1 and 3 is 3.
Total number of apples
= 3 u + 5 u + 10 u
= 18 u
18 u = 36
1 u = 36 ÷ 18 = 2
Number of apples in Container F
= 10 u
= 10 x 2
= 20
Number of starfruits in Container F
= 32 - 20
= 12
Percentage of the fruits in Container F are starfruits
=
1232 x 100%
= 37.5%
Answer(s): 37.5%