The average number of mangoes in Container H, Container J and Container K is 64 and it is 8 more than the average number of mangosteens in the 3 containers.
17 of the mangosteens are in Container H and the mangosteens in Container H is 80% of the number of mangosteens in Container J. If each container has the same number of fruits, what percentage of the fruits in Container K are mangoes?
Average number of mangosteens
= 64 - 8
= 56
Total number of mangosteens
= 3 x 56
= 168
Total number of mangoes
= 3 x 64
= 192
Total number of fruits
= 168 + 192
= 360
Number of fruits in each container
= 360 ÷ 3
= 120
Mangosteens in Container H |
Mangosteens in Container J |
Mangosteens in Container K |
Total mangosteens |
1x4 |
6x4 |
7x4 |
4x1 |
5x1 |
|
|
4 u |
5 u |
19 u |
28 u |
80% =
80100 =
45The number of mangosteens in Container H is repeated. Make the number of mangosteens in Container H the same. LCM of 1 and 4 is 4.
Total number of mangosteens
= 4 u + 5 u + 19 u
= 28 u
28 u = 168
1 u = 168 ÷ 28 = 6
Number of mangosteens in Container K
= 19 u
= 19 x 6
= 114
Number of mangoes in Container K
= 120 - 114
= 6
Percentage of the fruits in Container K are mangoes
=
6120 x 100%
= 5%
Answer(s): 5%