The average number of kiwis in Box R, Box S and Box T is 12 and it is 4 more than the average number of chikoos in the 3 boxes.
16 of the chikoos are in Box R and the chikoos in Box R is 40% of the number of chikoos in Box S. If each box has the same number of fruits, what percentage of the fruits in Box T are kiwis?
Average number of chikoos
= 12 - 4
= 8
Total number of chikoos
= 3 x 8
= 24
Total number of kiwis
= 3 x 12
= 36
Total number of fruits
= 24 + 36
= 60
Number of fruits in each box
= 60 ÷ 3
= 20
Chikoos in Box R |
Chikoos in Box S |
Chikoos in Box T |
Total chikoos |
1x2 |
5x2 |
6x2 |
2x1 |
5x1 |
|
|
2 u |
5 u |
5 u |
12 u |
40% =
40100 =
25The number of chikoos in Box R is repeated. Make the number of chikoos in Box R the same. LCM of 1 and 2 is 2.
Total number of chikoos
= 2 u + 5 u + 5 u
= 12 u
12 u = 24
1 u = 24 ÷ 12 = 2
Number of chikoos in Box T
= 5 u
= 5 x 2
= 10
Number of kiwis in Box T
= 20 - 10
= 10
Percentage of the fruits in Box T are kiwis
=
1020 x 100%
= 50%
Answer(s): 50%