The average number of chikoos in Container S, Container T and Container U is 20 and it is 5 more than the average number of pears in the 3 containers. ¹₅ of the pears are in Container S and the pears in Container S is 60% of the number of pears in Container T. If each container has the same number of fruits, what percentage of the fruits in Container U are chikoos?
Average number of pears
= 20 - 5
= 15

Total number of pears
= 3 x 15
= 45

Total number of chikoos
= 3 x 20 
= 60

Total number of fruits
= 45 + 60
= 105

Number of fruits in each container
= 105 ÷ 3
= 35

Pears in Container S	Pears in Container T	Pears in Container U	Total pears
1x3	4x3		5x3
3x1	5x1
3 u	5 u	7 u	15 u

60% = ⁶⁰₁₀₀ = ³₅

The number of pears in Container S is repeated.  Make the number of pears in Container S the same.  LCM of 1 and 3 is 3. 

Total number of pears
= 3 u + 5 u + 7 u
= 15 u

15 u = 45

1 u = 45 ÷ 15 = 3

Number of pears in Container U
= 7 u
= 7 x 3
= 21

Number of chikoos in Container U
= 35 - 21
= 14

Percentage of the fruits in Container U are chikoos
= ¹⁴₃₅ x 100%
= 40%

Answer(s): 40%