The average number of mangosteens in Container V, Container W and Container X is 45 and it is 10 more than the average number of pears in the 3 containers. ¹₅ of the pears are in Container V and the pears in Container V is 60% of the number of pears in Container W. If each container has the same number of fruits, what percentage of the fruits in Container X are mangosteens?
Average number of pears
= 45 - 10
= 35

Total number of pears
= 3 x 35
= 105

Total number of mangosteens
= 3 x 45 
= 135

Total number of fruits
= 105 + 135
= 240

Number of fruits in each container
= 240 ÷ 3
= 80

Pears in Container V	Pears in Container W	Pears in Container X	Total pears
1x3	4x3		5x3
3x1	5x1
3 u	5 u	7 u	15 u

60% = ⁶⁰₁₀₀ = ³₅

The number of pears in Container V is repeated.  Make the number of pears in Container V the same.  LCM of 1 and 3 is 3. 

Total number of pears
= 3 u + 5 u + 7 u
= 15 u

15 u = 105

1 u = 105 ÷ 15 = 7

Number of pears in Container X
= 7 u
= 7 x 7
= 49

Number of mangosteens in Container X
= 80 - 49
= 31

Percentage of the fruits in Container X are mangosteens
= ³¹₈₀ x 100%
= 38.75%

Answer(s): 38.75%