The average number of kiwis in Box X, Box Y and Box Z is 16 and it is 8 more than the average number of starfruits in the 3 boxes.
13 of the starfruits are in Box X and the starfruits in Box X is 80% of the number of starfruits in Box Y. If each box has the same number of fruits, what percentage of the fruits in Box Z are kiwis?
Average number of starfruits
= 16 - 8
= 8
Total number of starfruits
= 3 x 8
= 24
Total number of kiwis
= 3 x 16
= 48
Total number of fruits
= 24 + 48
= 72
Number of fruits in each box
= 72 ÷ 3
= 24
Starfruits in Box X |
Starfruits in Box Y |
Starfruits in Box Z |
Total starfruits |
1x4 |
2x4 |
3x4 |
4x1 |
5x1 |
|
|
4 u |
5 u |
3 u |
12 u |
80% =
80100 =
45The number of starfruits in Box X is repeated. Make the number of starfruits in Box X the same. LCM of 1 and 4 is 4.
Total number of starfruits
= 4 u + 5 u + 3 u
= 12 u
12 u = 24
1 u = 24 ÷ 12 = 2
Number of starfruits in Box Z
= 3 u
= 3 x 2
= 6
Number of kiwis in Box Z
= 24 - 6
= 18
Percentage of the fruits in Box Z are kiwis
=
1824 x 100%
= 75%
Answer(s): 75%