Three women, Joelle, Linda and Xylia went on a shopping spree. 90% of Joelle's spending was equal to
16 of Linda's spending. Xylia's spending was 40% more than Linda's. If Linda spent another $1080, she would spend the same amount of money as Xylia.
- Find the ratio of Joelle's spending to Linda's to Xylia's.
- How much did Joelle spend?
Joelle |
Linda |
Xylia |
5x5 |
27x5 |
|
|
5x27 |
7x27 |
25 u |
135 u |
189 u |
(a)
90%=
90100 =
910 910 of Joelle's spending is equal to
16 of Linda's spending. Make the numerators the same. LCM of 9 and 1 is 9.
910 of Joelle's spending =
16 of Linda's spending
910 of Joelle's spending =
1x96x9 of Linda's spending
910 of Joelle's spending =
954 of Linda's spending
Joelle : Linda
10 : 54
5 : 27
Xylia's spending in percent when compared to Linda's
= 100% + 40%
= 140%
Linda : Xylia
100 : 140
5 : 7
Linda's spending is the repeated identity. Make Linda's spending the same. LCM of 27 and 5 is 135.
Joelle : Linda : Xylia
25 : 135 : 189
(b)
|
Joelle |
Linda |
Xylia |
Before |
25 u |
135 u |
189 u |
Change |
|
+ 54 u |
|
After |
25 u |
189 u |
189 u |
Additional amount that Linda would have to spend to be the same as Xylia
= 189 u - 135 u
= 54 u
54 u = 1080
1 u = 1080 ÷ 54 = 20
Amount that Joelle spent
= 25 u
= 25 x 20
= $500
Answer(s): (a) 25 : 135 : 189; (b) $500