Three women, Jaslyn, Gabby and Linda went on a shopping spree. 90% of Jaslyn's spending was equal to
16 of Gabby's spending. Linda's spending was 70% less than Gabby's. If Gabby spent $5103 less, she would spend the same amount of money as Linda.
- Find the ratio of Jaslyn's spending to Gabby's to Linda's.
- How much did Linda spend?
Jaslyn |
Gabby |
Linda |
5x10 |
27x10 |
|
|
10x27 |
3x27 |
50 u |
270 u |
81 u |
(a)
90%=
90100 =
910 910 of Jaslyn's spending is equal to
16 of Gabby's spending. Make the numerators the same. LCM of 9 and 1 is 9.
910 of Jaslyn's spending =
16 of Gabby's spending
910 of Jaslyn's spending =
1x96x9 of Gabby's spending
910 of Jaslyn's spending =
954 of Gabby's spending
Jaslyn : Gabby
10 : 54
5 : 27
Linda's spending in percent when compared to Gabby's
= 100% - 70%
= 30%
Gabby : Linda
100 : 30
10 : 3
Gabby's spending is the repeated identity. Make Gabby's spending the same. LCM of 27 and 10 is 270.
Jaslyn : Gabby : Linda
50 : 270 : 81
(b)
|
Jaslyn |
Gabby |
Linda |
Before |
50 u |
270 u |
81 u |
Change |
|
- 189 u |
|
After |
50 u |
81 u |
81 u |
Additional amount that Gabby would have to spend less to be the same as Linda
= 270 u - 81 u
= 189 u
189 u = 5103
1 u = 5103 ÷ 189 = 27
Amount that Linda spent
= 81 u
= 81 x 27
= $2187
Answer(s): (a) 50 : 270 : 81; (b) $2187