Three women, Dana, Jade and Tiffany went on a shopping spree. 30% of Dana's spending was equal to
12 of Jade's spending. Tiffany's spending was 60% more than Jade's. If Jade spent another $513, she would spend the same amount of money as Tiffany.
- Find the ratio of Dana's spending to Jade's to Tiffany's.
- How much did Dana spend?
Dana |
Jade |
Tiffany |
5x5 |
3x5 |
|
|
5x3 |
8x3 |
25 u |
15 u |
24 u |
(a)
30%=
30100 =
310 310 of Dana's spending is equal to
12 of Jade's spending. Make the numerators the same. LCM of 3 and 1 is 3.
310 of Dana's spending =
12 of Jade's spending
310 of Dana's spending =
1x32x3 of Jade's spending
310 of Dana's spending =
36 of Jade's spending
Dana : Jade
10 : 6
5 : 3
Tiffany's spending in percent when compared to Jade's
= 100% + 60%
= 160%
Jade : Tiffany
100 : 160
5 : 8
Jade's spending is the repeated identity. Make Jade's spending the same. LCM of 3 and 5 is 15.
Dana : Jade : Tiffany
25 : 15 : 24
(b)
|
Dana |
Jade |
Tiffany |
Before |
25 u |
15 u |
24 u |
Change |
|
+ 9 u |
|
After |
25 u |
24 u |
24 u |
Additional amount that Jade would have to spend to be the same as Tiffany
= 24 u - 15 u
= 9 u
9 u = 513
1 u = 513 ÷ 9 = 57
Amount that Dana spent
= 25 u
= 25 x 57
= $1425
Answer(s): (a) 25 : 15 : 24; (b) $1425