Three women, Jade, Min and Nora went on a shopping spree. 70% of Jade's spending was equal to
12 of Min's spending. Nora's spending was 70% less than Min's. If Min spent $2695 less, she would spend the same amount of money as Nora.
- Find the ratio of Jade's spending to Min's to Nora's.
- How much did Nora spend?
Jade |
Min |
Nora |
5x10 |
7x10 |
|
|
10x7 |
3x7 |
50 u |
70 u |
21 u |
(a)
70%=
70100 =
710 710 of Jade's spending is equal to
12 of Min's spending. Make the numerators the same. LCM of 7 and 1 is 7.
710 of Jade's spending =
12 of Min's spending
710 of Jade's spending =
1x72x7 of Min's spending
710 of Jade's spending =
714 of Min's spending
Jade : Min
10 : 14
5 : 7
Nora's spending in percent when compared to Min's
= 100% - 70%
= 30%
Min : Nora
100 : 30
10 : 3
Min's spending is the repeated identity. Make Min's spending the same. LCM of 7 and 10 is 70.
Jade : Min : Nora
50 : 70 : 21
(b)
|
Jade |
Min |
Nora |
Before |
50 u |
70 u |
21 u |
Change |
|
- 49 u |
|
After |
50 u |
21 u |
21 u |
Additional amount that Min would have to spend less to be the same as Nora
= 70 u - 21 u
= 49 u
49 u = 2695
1 u = 2695 ÷ 49 = 55
Amount that Nora spent
= 21 u
= 21 x 55
= $1155
Answer(s): (a) 50 : 70 : 21; (b) $1155