Three women, Jaslyn, Shiyun and Risa went on a shopping spree. 30% of Jaslyn's spending was equal to
16 of Shiyun's spending. Risa's spending was 25% less than Shiyun's. If Shiyun spent $180 less, she would spend the same amount of money as Risa.
- Find the ratio of Jaslyn's spending to Shiyun's to Risa's.
- How much did Risa spend?
Jaslyn |
Shiyun |
Risa |
5x4 |
9x4 |
|
|
4x9 |
3x9 |
20 u |
36 u |
27 u |
(a)
30%=
30100 =
310 310 of Jaslyn's spending is equal to
16 of Shiyun's spending. Make the numerators the same. LCM of 3 and 1 is 3.
310 of Jaslyn's spending =
16 of Shiyun's spending
310 of Jaslyn's spending =
1x36x3 of Shiyun's spending
310 of Jaslyn's spending =
318 of Shiyun's spending
Jaslyn : Shiyun
10 : 18
5 : 9
Risa's spending in percent when compared to Shiyun's
= 100% - 25%
= 75%
Shiyun : Risa
100 : 75
4 : 3
Shiyun's spending is the repeated identity. Make Shiyun's spending the same. LCM of 9 and 4 is 36.
Jaslyn : Shiyun : Risa
20 : 36 : 27
(b)
|
Jaslyn |
Shiyun |
Risa |
Before |
20 u |
36 u |
27 u |
Change |
|
- 9 u |
|
After |
20 u |
27 u |
27 u |
Additional amount that Shiyun would have to spend less to be the same as Risa
= 36 u - 27 u
= 9 u
9 u = 180
1 u = 180 ÷ 9 = 20
Amount that Risa spent
= 27 u
= 27 x 20
= $540
Answer(s): (a) 20 : 36 : 27; (b) $540