Three women, Shannon, Marion and Jean went on a shopping spree. 90% of Shannon's spending was equal to
15 of Marion's spending. Jean's spending was 60% less than Marion's. If Marion spent $621 less, she would spend the same amount of money as Jean.
- Find the ratio of Shannon's spending to Marion's to Jean's.
- How much did Jean spend?
Shannon |
Marion |
Jean |
2x5 |
9x5 |
|
|
5x9 |
2x9 |
10 u |
45 u |
18 u |
(a)
90%=
90100 =
910 910 of Shannon's spending is equal to
15 of Marion's spending. Make the numerators the same. LCM of 9 and 1 is 9.
910 of Shannon's spending =
15 of Marion's spending
910 of Shannon's spending =
1x95x9 of Marion's spending
910 of Shannon's spending =
945 of Marion's spending
Shannon : Marion
10 : 45
2 : 9
Jean's spending in percent when compared to Marion's
= 100% - 60%
= 40%
Marion : Jean
100 : 40
5 : 2
Marion's spending is the repeated identity. Make Marion's spending the same. LCM of 9 and 5 is 45.
Shannon : Marion : Jean
10 : 45 : 18
(b)
|
Shannon |
Marion |
Jean |
Before |
10 u |
45 u |
18 u |
Change |
|
- 27 u |
|
After |
10 u |
18 u |
18 u |
Additional amount that Marion would have to spend less to be the same as Jean
= 45 u - 18 u
= 27 u
27 u = 621
1 u = 621 ÷ 27 = 23
Amount that Jean spent
= 18 u
= 18 x 23
= $414
Answer(s): (a) 10 : 45 : 18; (b) $414