Three women, Kathy, Irene and Esther went on a shopping spree. 70% of Kathy's spending was equal to
16 of Irene's spending. Esther's spending was 80% less than Irene's. If Irene spent $9072 less, she would spend the same amount of money as Esther.
- Find the ratio of Kathy's spending to Irene's to Esther's.
- How much did Esther spend?
Kathy |
Irene |
Esther |
5x5 |
21x5 |
|
|
5x21 |
1x21 |
25 u |
105 u |
21 u |
(a)
70%=
70100 =
710 710 of Kathy's spending is equal to
16 of Irene's spending. Make the numerators the same. LCM of 7 and 1 is 7.
710 of Kathy's spending =
16 of Irene's spending
710 of Kathy's spending =
1x76x7 of Irene's spending
710 of Kathy's spending =
742 of Irene's spending
Kathy : Irene
10 : 42
5 : 21
Esther's spending in percent when compared to Irene's
= 100% - 80%
= 20%
Irene : Esther
100 : 20
5 : 1
Irene's spending is the repeated identity. Make Irene's spending the same. LCM of 21 and 5 is 105.
Kathy : Irene : Esther
25 : 105 : 21
(b)
|
Kathy |
Irene |
Esther |
Before |
25 u |
105 u |
21 u |
Change |
|
- 84 u |
|
After |
25 u |
21 u |
21 u |
Additional amount that Irene would have to spend less to be the same as Esther
= 105 u - 21 u
= 84 u
84 u = 9072
1 u = 9072 ÷ 84 = 108
Amount that Esther spent
= 21 u
= 21 x 108
= $2268
Answer(s): (a) 25 : 105 : 21; (b) $2268