Three women, Hazel, Shiyun and Joelle went on a shopping spree. 70% of Hazel's spending was equal to
12 of Shiyun's spending. Joelle's spending was 80% less than Shiyun's. If Shiyun spent $588 less, she would spend the same amount of money as Joelle.
- Find the ratio of Hazel's spending to Shiyun's to Joelle's.
- How much did Joelle spend?
Hazel |
Shiyun |
Joelle |
5x5 |
7x5 |
|
|
5x7 |
1x7 |
25 u |
35 u |
7 u |
(a)
70%=
70100 =
710 710 of Hazel's spending is equal to
12 of Shiyun's spending. Make the numerators the same. LCM of 7 and 1 is 7.
710 of Hazel's spending =
12 of Shiyun's spending
710 of Hazel's spending =
1x72x7 of Shiyun's spending
710 of Hazel's spending =
714 of Shiyun's spending
Hazel : Shiyun
10 : 14
5 : 7
Joelle's spending in percent when compared to Shiyun's
= 100% - 80%
= 20%
Shiyun : Joelle
100 : 20
5 : 1
Shiyun's spending is the repeated identity. Make Shiyun's spending the same. LCM of 7 and 5 is 35.
Hazel : Shiyun : Joelle
25 : 35 : 7
(b)
|
Hazel |
Shiyun |
Joelle |
Before |
25 u |
35 u |
7 u |
Change |
|
- 28 u |
|
After |
25 u |
7 u |
7 u |
Additional amount that Shiyun would have to spend less to be the same as Joelle
= 35 u - 7 u
= 28 u
28 u = 588
1 u = 588 ÷ 28 = 21
Amount that Joelle spent
= 7 u
= 7 x 21
= $147
Answer(s): (a) 25 : 35 : 7; (b) $147