Three women, Marion, Natalie and Jaslyn went on a shopping spree. 70% of Marion's spending was equal to ¹₂ of Natalie's spending. Jaslyn's spending was  70% less than Natalie's. If Natalie spent $1372 less, she would spend the same amount of money as Jaslyn.

1. Find the ratio of Marion's spending to Natalie's to Jaslyn's.
2. How much did Jaslyn spend?

Marion	Natalie	Jaslyn
5x10	7x10
	10x7	3x7
50 u	70 u	21 u

(a)
70%= ⁷⁰₁₀₀ = ⁷₁₀
⁷₁₀ of Marion's spending is equal to ¹₂ of Natalie's spending. Make the numerators the same.  LCM of 7 and 1 is 7.

710 of Marion's spending = 12 of Natalie's spending
710 of Marion's spending =1x72x7 of Natalie's spending
710 of Marion's spending = 714 of Natalie's spending

Marion : Natalie
10 : 14
5 : 7

Jaslyn's spending in percent when compared to Natalie's
= 100% - 70%
= 30%

Natalie : Jaslyn
100 : 30
10 : 3

Natalie's spending is the repeated identity.  Make Natalie's spending the same.  LCM of 7 and 10 is 70.

Marion : Natalie : Jaslyn
50 : 70 : 21

(b)

	Marion	Natalie	Jaslyn
Before	50 u	70 u	21 u
Change		- 49 u
After	50 u	21 u	21 u

Additional amount that Natalie would have to spend less to be the same as Jaslyn
= 70 u - 21 u
= 49 u

49 u = 1372

1 u = 1372 ÷ 49 = 28

Amount that Jaslyn spent
= 21 u
= 21 x 28
= $588 

Answer(s): (a) 50 : 70 : 21; (b) $588