Three women, Jane, Abi and Sarah went on a shopping spree. 90% of Jane's spending was equal to
15 of Abi's spending. Sarah's spending was 70% less than Abi's. If Abi spent $6426 less, she would spend the same amount of money as Sarah.
- Find the ratio of Jane's spending to Abi's to Sarah's.
- How much did Sarah spend?
Jane |
Abi |
Sarah |
2x10 |
9x10 |
|
|
10x9 |
3x9 |
20 u |
90 u |
27 u |
(a)
90%=
90100 =
910 910 of Jane's spending is equal to
15 of Abi's spending. Make the numerators the same. LCM of 9 and 1 is 9.
910 of Jane's spending =
15 of Abi's spending
910 of Jane's spending =
1x95x9 of Abi's spending
910 of Jane's spending =
945 of Abi's spending
Jane : Abi
10 : 45
2 : 9
Sarah's spending in percent when compared to Abi's
= 100% - 70%
= 30%
Abi : Sarah
100 : 30
10 : 3
Abi's spending is the repeated identity. Make Abi's spending the same. LCM of 9 and 10 is 90.
Jane : Abi : Sarah
20 : 90 : 27
(b)
|
Jane |
Abi |
Sarah |
Before |
20 u |
90 u |
27 u |
Change |
|
- 63 u |
|
After |
20 u |
27 u |
27 u |
Additional amount that Abi would have to spend less to be the same as Sarah
= 90 u - 27 u
= 63 u
63 u = 6426
1 u = 6426 ÷ 63 = 102
Amount that Sarah spent
= 27 u
= 27 x 102
= $2754
Answer(s): (a) 20 : 90 : 27; (b) $2754