Three women, Marion, Tina and Lucy went on a shopping spree. 70% of Marion's spending was equal to
15 of Tina's spending. Lucy's spending was 60% more than Tina's. If Tina spent another $1680, she would spend the same amount of money as Lucy.
- Find the ratio of Marion's spending to Tina's to Lucy's.
- How much did Marion spend?
Marion |
Tina |
Lucy |
2x5 |
7x5 |
|
|
5x7 |
8x7 |
10 u |
35 u |
56 u |
(a)
70%=
70100 =
710 710 of Marion's spending is equal to
15 of Tina's spending. Make the numerators the same. LCM of 7 and 1 is 7.
710 of Marion's spending =
15 of Tina's spending
710 of Marion's spending =
1x75x7 of Tina's spending
710 of Marion's spending =
735 of Tina's spending
Marion : Tina
10 : 35
2 : 7
Lucy's spending in percent when compared to Tina's
= 100% + 60%
= 160%
Tina : Lucy
100 : 160
5 : 8
Tina's spending is the repeated identity. Make Tina's spending the same. LCM of 7 and 5 is 35.
Marion : Tina : Lucy
10 : 35 : 56
(b)
|
Marion |
Tina |
Lucy |
Before |
10 u |
35 u |
56 u |
Change |
|
+ 21 u |
|
After |
10 u |
56 u |
56 u |
Additional amount that Tina would have to spend to be the same as Lucy
= 56 u - 35 u
= 21 u
21 u = 1680
1 u = 1680 ÷ 21 = 80
Amount that Marion spent
= 10 u
= 10 x 80
= $800
Answer(s): (a) 10 : 35 : 56; (b) $800