Three women, Kimberly, Roshel and Zoe went on a shopping spree. 90% of Kimberly's spending was equal to
15 of Roshel's spending. Zoe's spending was 40% more than Roshel's. If Roshel spent another $1998, she would spend the same amount of money as Zoe.
- Find the ratio of Kimberly's spending to Roshel's to Zoe's.
- How much did Kimberly spend?
Kimberly |
Roshel |
Zoe |
2x5 |
9x5 |
|
|
5x9 |
7x9 |
10 u |
45 u |
63 u |
(a)
90%=
90100 =
910 910 of Kimberly's spending is equal to
15 of Roshel's spending. Make the numerators the same. LCM of 9 and 1 is 9.
910 of Kimberly's spending =
15 of Roshel's spending
910 of Kimberly's spending =
1x95x9 of Roshel's spending
910 of Kimberly's spending =
945 of Roshel's spending
Kimberly : Roshel
10 : 45
2 : 9
Zoe's spending in percent when compared to Roshel's
= 100% + 40%
= 140%
Roshel : Zoe
100 : 140
5 : 7
Roshel's spending is the repeated identity. Make Roshel's spending the same. LCM of 9 and 5 is 45.
Kimberly : Roshel : Zoe
10 : 45 : 63
(b)
|
Kimberly |
Roshel |
Zoe |
Before |
10 u |
45 u |
63 u |
Change |
|
+ 18 u |
|
After |
10 u |
63 u |
63 u |
Additional amount that Roshel would have to spend to be the same as Zoe
= 63 u - 45 u
= 18 u
18 u = 1998
1 u = 1998 ÷ 18 = 111
Amount that Kimberly spent
= 10 u
= 10 x 111
= $1110
Answer(s): (a) 10 : 45 : 63; (b) $1110