Three women, Kathy, Nora and Tina went on a shopping spree. 90% of Kathy's spending was equal to
12 of Nora's spending. Tina's spending was 40% more than Nora's. If Nora spent another $774, she would spend the same amount of money as Tina.
- Find the ratio of Kathy's spending to Nora's to Tina's.
- How much did Kathy spend?
Kathy |
Nora |
Tina |
5x5 |
9x5 |
|
|
5x9 |
7x9 |
25 u |
45 u |
63 u |
(a)
90%=
90100 =
910 910 of Kathy's spending is equal to
12 of Nora's spending. Make the numerators the same. LCM of 9 and 1 is 9.
910 of Kathy's spending =
12 of Nora's spending
910 of Kathy's spending =
1x92x9 of Nora's spending
910 of Kathy's spending =
918 of Nora's spending
Kathy : Nora
10 : 18
5 : 9
Tina's spending in percent when compared to Nora's
= 100% + 40%
= 140%
Nora : Tina
100 : 140
5 : 7
Nora's spending is the repeated identity. Make Nora's spending the same. LCM of 9 and 5 is 45.
Kathy : Nora : Tina
25 : 45 : 63
(b)
|
Kathy |
Nora |
Tina |
Before |
25 u |
45 u |
63 u |
Change |
|
+ 18 u |
|
After |
25 u |
63 u |
63 u |
Additional amount that Nora would have to spend to be the same as Tina
= 63 u - 45 u
= 18 u
18 u = 774
1 u = 774 ÷ 18 = 43
Amount that Kathy spent
= 25 u
= 25 x 43
= $1075
Answer(s): (a) 25 : 45 : 63; (b) $1075