Three women, Shannon, Jaslyn and Jen went on a shopping spree. 90% of Shannon's spending was equal to
12 of Jaslyn's spending. Jen's spending was 25% less than Jaslyn's. If Jaslyn spent $720 less, she would spend the same amount of money as Jen.
- Find the ratio of Shannon's spending to Jaslyn's to Jen's.
- How much did Jen spend?
Shannon |
Jaslyn |
Jen |
5x4 |
9x4 |
|
|
4x9 |
3x9 |
20 u |
36 u |
27 u |
(a)
90%=
90100 =
910 910 of Shannon's spending is equal to
12 of Jaslyn's spending. Make the numerators the same. LCM of 9 and 1 is 9.
910 of Shannon's spending =
12 of Jaslyn's spending
910 of Shannon's spending =
1x92x9 of Jaslyn's spending
910 of Shannon's spending =
918 of Jaslyn's spending
Shannon : Jaslyn
10 : 18
5 : 9
Jen's spending in percent when compared to Jaslyn's
= 100% - 25%
= 75%
Jaslyn : Jen
100 : 75
4 : 3
Jaslyn's spending is the repeated identity. Make Jaslyn's spending the same. LCM of 9 and 4 is 36.
Shannon : Jaslyn : Jen
20 : 36 : 27
(b)
|
Shannon |
Jaslyn |
Jen |
Before |
20 u |
36 u |
27 u |
Change |
|
- 9 u |
|
After |
20 u |
27 u |
27 u |
Additional amount that Jaslyn would have to spend less to be the same as Jen
= 36 u - 27 u
= 9 u
9 u = 720
1 u = 720 ÷ 9 = 80
Amount that Jen spent
= 27 u
= 27 x 80
= $2160
Answer(s): (a) 20 : 36 : 27; (b) $2160