Three women, Jaslyn, Pamela and Gabby went on a shopping spree. 90% of Jaslyn's spending was equal to
15 of Pamela's spending. Gabby's spending was 50% more than Pamela's. If Pamela spent another $882, she would spend the same amount of money as Gabby.
- Find the ratio of Jaslyn's spending to Pamela's to Gabby's.
- How much did Jaslyn spend?
Jaslyn |
Pamela |
Gabby |
2x2 |
9x2 |
|
|
2x9 |
3x9 |
4 u |
18 u |
27 u |
(a)
90%=
90100 =
910 910 of Jaslyn's spending is equal to
15 of Pamela's spending. Make the numerators the same. LCM of 9 and 1 is 9.
910 of Jaslyn's spending =
15 of Pamela's spending
910 of Jaslyn's spending =
1x95x9 of Pamela's spending
910 of Jaslyn's spending =
945 of Pamela's spending
Jaslyn : Pamela
10 : 45
2 : 9
Gabby's spending in percent when compared to Pamela's
= 100% + 50%
= 150%
Pamela : Gabby
100 : 150
2 : 3
Pamela's spending is the repeated identity. Make Pamela's spending the same. LCM of 9 and 2 is 18.
Jaslyn : Pamela : Gabby
4 : 18 : 27
(b)
|
Jaslyn |
Pamela |
Gabby |
Before |
4 u |
18 u |
27 u |
Change |
|
+ 9 u |
|
After |
4 u |
27 u |
27 u |
Additional amount that Pamela would have to spend to be the same as Gabby
= 27 u - 18 u
= 9 u
9 u = 882
1 u = 882 ÷ 9 = 98
Amount that Jaslyn spent
= 4 u
= 4 x 98
= $392
Answer(s): (a) 4 : 18 : 27; (b) $392