Three women, Hilda, Tina and Eva went on a shopping spree. 30% of Hilda's spending was equal to
12 of Tina's spending. Eva's spending was 70% less than Tina's. If Tina spent $2457 less, she would spend the same amount of money as Eva.
- Find the ratio of Hilda's spending to Tina's to Eva's.
- How much did Eva spend?
Hilda |
Tina |
Eva |
5x10 |
3x10 |
|
|
10x3 |
3x3 |
50 u |
30 u |
9 u |
(a)
30%=
30100 =
310 310 of Hilda's spending is equal to
12 of Tina's spending. Make the numerators the same. LCM of 3 and 1 is 3.
310 of Hilda's spending =
12 of Tina's spending
310 of Hilda's spending =
1x32x3 of Tina's spending
310 of Hilda's spending =
36 of Tina's spending
Hilda : Tina
10 : 6
5 : 3
Eva's spending in percent when compared to Tina's
= 100% - 70%
= 30%
Tina : Eva
100 : 30
10 : 3
Tina's spending is the repeated identity. Make Tina's spending the same. LCM of 3 and 10 is 30.
Hilda : Tina : Eva
50 : 30 : 9
(b)
|
Hilda |
Tina |
Eva |
Before |
50 u |
30 u |
9 u |
Change |
|
- 21 u |
|
After |
50 u |
9 u |
9 u |
Additional amount that Tina would have to spend less to be the same as Eva
= 30 u - 9 u
= 21 u
21 u = 2457
1 u = 2457 ÷ 21 = 117
Amount that Eva spent
= 9 u
= 9 x 117
= $1053
Answer(s): (a) 50 : 30 : 9; (b) $1053