Three women, Dana, Tiffany and Marion went on a shopping spree. 30% of Dana's spending was equal to
16 of Tiffany's spending. Marion's spending was 70% less than Tiffany's. If Tiffany spent $7119 less, she would spend the same amount of money as Marion.
- Find the ratio of Dana's spending to Tiffany's to Marion's.
- How much did Marion spend?
Dana |
Tiffany |
Marion |
5x10 |
9x10 |
|
|
10x9 |
3x9 |
50 u |
90 u |
27 u |
(a)
30%=
30100 =
310 310 of Dana's spending is equal to
16 of Tiffany's spending. Make the numerators the same. LCM of 3 and 1 is 3.
310 of Dana's spending =
16 of Tiffany's spending
310 of Dana's spending =
1x36x3 of Tiffany's spending
310 of Dana's spending =
318 of Tiffany's spending
Dana : Tiffany
10 : 18
5 : 9
Marion's spending in percent when compared to Tiffany's
= 100% - 70%
= 30%
Tiffany : Marion
100 : 30
10 : 3
Tiffany's spending is the repeated identity. Make Tiffany's spending the same. LCM of 9 and 10 is 90.
Dana : Tiffany : Marion
50 : 90 : 27
(b)
|
Dana |
Tiffany |
Marion |
Before |
50 u |
90 u |
27 u |
Change |
|
- 63 u |
|
After |
50 u |
27 u |
27 u |
Additional amount that Tiffany would have to spend less to be the same as Marion
= 90 u - 27 u
= 63 u
63 u = 7119
1 u = 7119 ÷ 63 = 113
Amount that Marion spent
= 27 u
= 27 x 113
= $3051
Answer(s): (a) 50 : 90 : 27; (b) $3051