Three women, Penelope, Tina and Tiffany went on a shopping spree. 70% of Penelope's spending was equal to
16 of Tina's spending. Tiffany's spending was 50% more than Tina's. If Tina spent another $1869, she would spend the same amount of money as Tiffany.
- Find the ratio of Penelope's spending to Tina's to Tiffany's.
- How much did Penelope spend?
Penelope |
Tina |
Tiffany |
5x2 |
21x2 |
|
|
2x21 |
3x21 |
10 u |
42 u |
63 u |
(a)
70%=
70100 =
710 710 of Penelope's spending is equal to
16 of Tina's spending. Make the numerators the same. LCM of 7 and 1 is 7.
710 of Penelope's spending =
16 of Tina's spending
710 of Penelope's spending =
1x76x7 of Tina's spending
710 of Penelope's spending =
742 of Tina's spending
Penelope : Tina
10 : 42
5 : 21
Tiffany's spending in percent when compared to Tina's
= 100% + 50%
= 150%
Tina : Tiffany
100 : 150
2 : 3
Tina's spending is the repeated identity. Make Tina's spending the same. LCM of 21 and 2 is 42.
Penelope : Tina : Tiffany
10 : 42 : 63
(b)
|
Penelope |
Tina |
Tiffany |
Before |
10 u |
42 u |
63 u |
Change |
|
+ 21 u |
|
After |
10 u |
63 u |
63 u |
Additional amount that Tina would have to spend to be the same as Tiffany
= 63 u - 42 u
= 21 u
21 u = 1869
1 u = 1869 ÷ 21 = 89
Amount that Penelope spent
= 10 u
= 10 x 89
= $890
Answer(s): (a) 10 : 42 : 63; (b) $890