Three women, Esther, Winnie and Min went on a shopping spree. 90% of Esther's spending was equal to
12 of Winnie's spending. Min's spending was 40% more than Winnie's. If Winnie spent another $1242, she would spend the same amount of money as Min.
- Find the ratio of Esther's spending to Winnie's to Min's.
- How much did Esther spend?
Esther |
Winnie |
Min |
5x5 |
9x5 |
|
|
5x9 |
7x9 |
25 u |
45 u |
63 u |
(a)
90%=
90100 =
910 910 of Esther's spending is equal to
12 of Winnie's spending. Make the numerators the same. LCM of 9 and 1 is 9.
910 of Esther's spending =
12 of Winnie's spending
910 of Esther's spending =
1x92x9 of Winnie's spending
910 of Esther's spending =
918 of Winnie's spending
Esther : Winnie
10 : 18
5 : 9
Min's spending in percent when compared to Winnie's
= 100% + 40%
= 140%
Winnie : Min
100 : 140
5 : 7
Winnie's spending is the repeated identity. Make Winnie's spending the same. LCM of 9 and 5 is 45.
Esther : Winnie : Min
25 : 45 : 63
(b)
|
Esther |
Winnie |
Min |
Before |
25 u |
45 u |
63 u |
Change |
|
+ 18 u |
|
After |
25 u |
63 u |
63 u |
Additional amount that Winnie would have to spend to be the same as Min
= 63 u - 45 u
= 18 u
18 u = 1242
1 u = 1242 ÷ 18 = 69
Amount that Esther spent
= 25 u
= 25 x 69
= $1725
Answer(s): (a) 25 : 45 : 63; (b) $1725