Three women, Cathy, Nora and Kimberly went on a shopping spree. 70% of Cathy's spending was equal to
15 of Nora's spending. Kimberly's spending was 70% less than Nora's. If Nora spent $3087 less, she would spend the same amount of money as Kimberly.
- Find the ratio of Cathy's spending to Nora's to Kimberly's.
- How much did Kimberly spend?
Cathy |
Nora |
Kimberly |
2x10 |
7x10 |
|
|
10x7 |
3x7 |
20 u |
70 u |
21 u |
(a)
70%=
70100 =
710 710 of Cathy's spending is equal to
15 of Nora's spending. Make the numerators the same. LCM of 7 and 1 is 7.
710 of Cathy's spending =
15 of Nora's spending
710 of Cathy's spending =
1x75x7 of Nora's spending
710 of Cathy's spending =
735 of Nora's spending
Cathy : Nora
10 : 35
2 : 7
Kimberly's spending in percent when compared to Nora's
= 100% - 70%
= 30%
Nora : Kimberly
100 : 30
10 : 3
Nora's spending is the repeated identity. Make Nora's spending the same. LCM of 7 and 10 is 70.
Cathy : Nora : Kimberly
20 : 70 : 21
(b)
|
Cathy |
Nora |
Kimberly |
Before |
20 u |
70 u |
21 u |
Change |
|
- 49 u |
|
After |
20 u |
21 u |
21 u |
Additional amount that Nora would have to spend less to be the same as Kimberly
= 70 u - 21 u
= 49 u
49 u = 3087
1 u = 3087 ÷ 49 = 63
Amount that Kimberly spent
= 21 u
= 21 x 63
= $1323
Answer(s): (a) 20 : 70 : 21; (b) $1323