Three women, Marion, Dana and Gwen went on a shopping spree. 90% of Marion's spending was equal to
16 of Dana's spending. Gwen's spending was 25% less than Dana's. If Dana spent $1836 less, she would spend the same amount of money as Gwen.
- Find the ratio of Marion's spending to Dana's to Gwen's.
- How much did Gwen spend?
Marion |
Dana |
Gwen |
5x4 |
27x4 |
|
|
4x27 |
3x27 |
20 u |
108 u |
81 u |
(a)
90%=
90100 =
910 910 of Marion's spending is equal to
16 of Dana's spending. Make the numerators the same. LCM of 9 and 1 is 9.
910 of Marion's spending =
16 of Dana's spending
910 of Marion's spending =
1x96x9 of Dana's spending
910 of Marion's spending =
954 of Dana's spending
Marion : Dana
10 : 54
5 : 27
Gwen's spending in percent when compared to Dana's
= 100% - 25%
= 75%
Dana : Gwen
100 : 75
4 : 3
Dana's spending is the repeated identity. Make Dana's spending the same. LCM of 27 and 4 is 108.
Marion : Dana : Gwen
20 : 108 : 81
(b)
|
Marion |
Dana |
Gwen |
Before |
20 u |
108 u |
81 u |
Change |
|
- 27 u |
|
After |
20 u |
81 u |
81 u |
Additional amount that Dana would have to spend less to be the same as Gwen
= 108 u - 81 u
= 27 u
27 u = 1836
1 u = 1836 ÷ 27 = 68
Amount that Gwen spent
= 81 u
= 81 x 68
= $5508
Answer(s): (a) 20 : 108 : 81; (b) $5508