Three women, Jane, Elyse and Shiyun went on a shopping spree. 90% of Jane's spending was equal to
12 of Elyse's spending. Shiyun's spending was 50% more than Elyse's. If Elyse spent another $792, she would spend the same amount of money as Shiyun.
- Find the ratio of Jane's spending to Elyse's to Shiyun's.
- How much did Jane spend?
Jane |
Elyse |
Shiyun |
5x2 |
9x2 |
|
|
2x9 |
3x9 |
10 u |
18 u |
27 u |
(a)
90%=
90100 =
910 910 of Jane's spending is equal to
12 of Elyse's spending. Make the numerators the same. LCM of 9 and 1 is 9.
910 of Jane's spending =
12 of Elyse's spending
910 of Jane's spending =
1x92x9 of Elyse's spending
910 of Jane's spending =
918 of Elyse's spending
Jane : Elyse
10 : 18
5 : 9
Shiyun's spending in percent when compared to Elyse's
= 100% + 50%
= 150%
Elyse : Shiyun
100 : 150
2 : 3
Elyse's spending is the repeated identity. Make Elyse's spending the same. LCM of 9 and 2 is 18.
Jane : Elyse : Shiyun
10 : 18 : 27
(b)
|
Jane |
Elyse |
Shiyun |
Before |
10 u |
18 u |
27 u |
Change |
|
+ 9 u |
|
After |
10 u |
27 u |
27 u |
Additional amount that Elyse would have to spend to be the same as Shiyun
= 27 u - 18 u
= 9 u
9 u = 792
1 u = 792 ÷ 9 = 88
Amount that Jane spent
= 10 u
= 10 x 88
= $880
Answer(s): (a) 10 : 18 : 27; (b) $880