Three women, Shiyun, Tammy and Jean went on a shopping spree. 70% of Shiyun's spending was equal to
15 of Tammy's spending. Jean's spending was 60% more than Tammy's. If Tammy spent another $1197, she would spend the same amount of money as Jean.
- Find the ratio of Shiyun's spending to Tammy's to Jean's.
- How much did Shiyun spend?
Shiyun |
Tammy |
Jean |
2x5 |
7x5 |
|
|
5x7 |
8x7 |
10 u |
35 u |
56 u |
(a)
70%=
70100 =
710 710 of Shiyun's spending is equal to
15 of Tammy's spending. Make the numerators the same. LCM of 7 and 1 is 7.
710 of Shiyun's spending =
15 of Tammy's spending
710 of Shiyun's spending =
1x75x7 of Tammy's spending
710 of Shiyun's spending =
735 of Tammy's spending
Shiyun : Tammy
10 : 35
2 : 7
Jean's spending in percent when compared to Tammy's
= 100% + 60%
= 160%
Tammy : Jean
100 : 160
5 : 8
Tammy's spending is the repeated identity. Make Tammy's spending the same. LCM of 7 and 5 is 35.
Shiyun : Tammy : Jean
10 : 35 : 56
(b)
|
Shiyun |
Tammy |
Jean |
Before |
10 u |
35 u |
56 u |
Change |
|
+ 21 u |
|
After |
10 u |
56 u |
56 u |
Additional amount that Tammy would have to spend to be the same as Jean
= 56 u - 35 u
= 21 u
21 u = 1197
1 u = 1197 ÷ 21 = 57
Amount that Shiyun spent
= 10 u
= 10 x 57
= $570
Answer(s): (a) 10 : 35 : 56; (b) $570