Three women, Marion, Abi and Pamela went on a shopping spree. 30% of Marion's spending was equal to
15 of Abi's spending. Pamela's spending was 70% less than Abi's. If Abi spent $798 less, she would spend the same amount of money as Pamela.
- Find the ratio of Marion's spending to Abi's to Pamela's.
- How much did Pamela spend?
Marion |
Abi |
Pamela |
2x10 |
3x10 |
|
|
10x3 |
3x3 |
20 u |
30 u |
9 u |
(a)
30%=
30100 =
310 310 of Marion's spending is equal to
15 of Abi's spending. Make the numerators the same. LCM of 3 and 1 is 3.
310 of Marion's spending =
15 of Abi's spending
310 of Marion's spending =
1x35x3 of Abi's spending
310 of Marion's spending =
315 of Abi's spending
Marion : Abi
10 : 15
2 : 3
Pamela's spending in percent when compared to Abi's
= 100% - 70%
= 30%
Abi : Pamela
100 : 30
10 : 3
Abi's spending is the repeated identity. Make Abi's spending the same. LCM of 3 and 10 is 30.
Marion : Abi : Pamela
20 : 30 : 9
(b)
|
Marion |
Abi |
Pamela |
Before |
20 u |
30 u |
9 u |
Change |
|
- 21 u |
|
After |
20 u |
9 u |
9 u |
Additional amount that Abi would have to spend less to be the same as Pamela
= 30 u - 9 u
= 21 u
21 u = 798
1 u = 798 ÷ 21 = 38
Amount that Pamela spent
= 9 u
= 9 x 38
= $342
Answer(s): (a) 20 : 30 : 9; (b) $342