Three women, Esther, Barbara and Lynn went on a shopping spree. 70% of Esther's spending was equal to
16 of Barbara's spending. Lynn's spending was 25% less than Barbara's. If Barbara spent $819 less, she would spend the same amount of money as Lynn.
- Find the ratio of Esther's spending to Barbara's to Lynn's.
- How much did Lynn spend?
Esther |
Barbara |
Lynn |
5x4 |
21x4 |
|
|
4x21 |
3x21 |
20 u |
84 u |
63 u |
(a)
70%=
70100 =
710 710 of Esther's spending is equal to
16 of Barbara's spending. Make the numerators the same. LCM of 7 and 1 is 7.
710 of Esther's spending =
16 of Barbara's spending
710 of Esther's spending =
1x76x7 of Barbara's spending
710 of Esther's spending =
742 of Barbara's spending
Esther : Barbara
10 : 42
5 : 21
Lynn's spending in percent when compared to Barbara's
= 100% - 25%
= 75%
Barbara : Lynn
100 : 75
4 : 3
Barbara's spending is the repeated identity. Make Barbara's spending the same. LCM of 21 and 4 is 84.
Esther : Barbara : Lynn
20 : 84 : 63
(b)
|
Esther |
Barbara |
Lynn |
Before |
20 u |
84 u |
63 u |
Change |
|
- 21 u |
|
After |
20 u |
63 u |
63 u |
Additional amount that Barbara would have to spend less to be the same as Lynn
= 84 u - 63 u
= 21 u
21 u = 819
1 u = 819 ÷ 21 = 39
Amount that Lynn spent
= 63 u
= 63 x 39
= $2457
Answer(s): (a) 20 : 84 : 63; (b) $2457