Three women, Esther, Vanessa and Jaslyn went on a shopping spree. 70% of Esther's spending was equal to
12 of Vanessa's spending. Jaslyn's spending was 25% less than Vanessa's. If Vanessa spent $476 less, she would spend the same amount of money as Jaslyn.
- Find the ratio of Esther's spending to Vanessa's to Jaslyn's.
- How much did Jaslyn spend?
Esther |
Vanessa |
Jaslyn |
5x4 |
7x4 |
|
|
4x7 |
3x7 |
20 u |
28 u |
21 u |
(a)
70%=
70100 =
710 710 of Esther's spending is equal to
12 of Vanessa's spending. Make the numerators the same. LCM of 7 and 1 is 7.
710 of Esther's spending =
12 of Vanessa's spending
710 of Esther's spending =
1x72x7 of Vanessa's spending
710 of Esther's spending =
714 of Vanessa's spending
Esther : Vanessa
10 : 14
5 : 7
Jaslyn's spending in percent when compared to Vanessa's
= 100% - 25%
= 75%
Vanessa : Jaslyn
100 : 75
4 : 3
Vanessa's spending is the repeated identity. Make Vanessa's spending the same. LCM of 7 and 4 is 28.
Esther : Vanessa : Jaslyn
20 : 28 : 21
(b)
|
Esther |
Vanessa |
Jaslyn |
Before |
20 u |
28 u |
21 u |
Change |
|
- 7 u |
|
After |
20 u |
21 u |
21 u |
Additional amount that Vanessa would have to spend less to be the same as Jaslyn
= 28 u - 21 u
= 7 u
7 u = 476
1 u = 476 ÷ 7 = 68
Amount that Jaslyn spent
= 21 u
= 21 x 68
= $1428
Answer(s): (a) 20 : 28 : 21; (b) $1428