Three women, Cathy, Eva and Xylia went on a shopping spree. 30% of Cathy's spending was equal to
12 of Eva's spending. Xylia's spending was 50% more than Eva's. If Eva spent another $258, she would spend the same amount of money as Xylia.
- Find the ratio of Cathy's spending to Eva's to Xylia's.
- How much did Cathy spend?
Cathy |
Eva |
Xylia |
5x2 |
3x2 |
|
|
2x3 |
3x3 |
10 u |
6 u |
9 u |
(a)
30%=
30100 =
310 310 of Cathy's spending is equal to
12 of Eva's spending. Make the numerators the same. LCM of 3 and 1 is 3.
310 of Cathy's spending =
12 of Eva's spending
310 of Cathy's spending =
1x32x3 of Eva's spending
310 of Cathy's spending =
36 of Eva's spending
Cathy : Eva
10 : 6
5 : 3
Xylia's spending in percent when compared to Eva's
= 100% + 50%
= 150%
Eva : Xylia
100 : 150
2 : 3
Eva's spending is the repeated identity. Make Eva's spending the same. LCM of 3 and 2 is 6.
Cathy : Eva : Xylia
10 : 6 : 9
(b)
|
Cathy |
Eva |
Xylia |
Before |
10 u |
6 u |
9 u |
Change |
|
+ 3 u |
|
After |
10 u |
9 u |
9 u |
Additional amount that Eva would have to spend to be the same as Xylia
= 9 u - 6 u
= 3 u
3 u = 258
1 u = 258 ÷ 3 = 86
Amount that Cathy spent
= 10 u
= 10 x 86
= $860
Answer(s): (a) 10 : 6 : 9; (b) $860