Glen, Jenson and Oliver had a total of 120 cards. The ratio of Jenson's cards to Oliver's cards was 2 : 7 at first. Glen and Jenson each gave away
12 of their cards. Given that the three boys had 102 cards left, how many cards did Glen have at first?
|
Glen |
Jenson |
Oliver |
Total |
Comparing Jenson and Oliver at first |
|
2 u |
7 u |
|
Before |
2 p |
2x1 = 2 u |
7 u |
120 |
Change |
- 1 p |
-1x1 = - 1 u |
|
- 18 |
After |
1 p |
1x1 = 1 u |
7 u |
102 |
Total number of cards that Glen and Jenson gave away
= 120 - 102
= 18
The number of cards that Jenson had at first is repeated. Make the number of cards that Jenson had at first the same. LCM of 2 and 2 is 2.
1 p + 1 u = 120 - 102
1 p + 1 u = 18
1 p = 18 - 1 u --- (1)
1 p + 1 u + 7 u = 102
1 p + 8 u = 102
1 p = 102 - 8 u --- (2)
(1) = (2)
18 - 1 u = 102 - 8 u
8 u - 1 u = 102 - 18
8 u - 1 u = 84
7 u = 84
1 u = 84 ÷ 7 = 12
Substitute 1 u = 12 into (1).
1 p = 18 - 1 u
1 p = 18 - 1 x 12
1 p = 18 - 12
1 p = 6
Number of cards that Glen had at first
= 2 p
= 2 x 6
= 12
Answer(s): 12