Brandon, Owen and Carl had a total of 134 cards. The ratio of Owen's cards to Carl's cards was 2 : 9 at first. Brandon and Owen each gave away
12 of their cards. Given that the three boys had 112 cards left, how many cards did Brandon have at first?
|
Brandon |
Owen |
Carl |
Total |
Comparing Owen and Carl at first |
|
2 u |
9 u |
|
Before |
2 p |
2x1 = 2 u |
9 u |
134 |
Change |
- 1 p |
-1x1 = - 1 u |
|
- 22 |
After |
1 p |
1x1 = 1 u |
9 u |
112 |
Total number of cards that Brandon and Owen gave away
= 134 - 112
= 22
The number of cards that Owen had at first is repeated. Make the number of cards that Owen had at first the same. LCM of 2 and 2 is 2.
1 p + 1 u = 134 - 112
1 p + 1 u = 22
1 p = 22 - 1 u --- (1)
1 p + 1 u + 9 u = 112
1 p + 10 u = 112
1 p = 112 - 10 u --- (2)
(1) = (2)
22 - 1 u = 112 - 10 u
10 u - 1 u = 112 - 22
10 u - 1 u = 90
9 u = 90
1 u = 90 ÷ 9 = 10
Substitute 1 u = 10 into (1).
1 p = 22 - 1 u
1 p = 22 - 1 x 10
1 p = 22 - 10
1 p = 12
Number of cards that Brandon had at first
= 2 p
= 2 x 12
= 24
Answer(s): 24