Fabian, Mark and John had a total of 58 marbles. The ratio of Mark's marbles to John's marbles was 6 : 5 at first. Fabian and Mark each gave away
12 of their marbles. Given that the three boys had 39 marbles left, how many marbles did Fabian have at first?
|
Fabian |
Mark |
John |
Total |
Comparing Mark and John at first |
|
6 u |
5 u |
|
Before |
2 p |
2x3 = 6 u |
5 u |
58 |
Change |
- 1 p |
-1x3 = - 3 u |
|
- 19 |
After |
1 p |
1x3 = 3 u |
5 u |
39 |
Total number of marbles that Fabian and Mark gave away
= 58 - 39
= 19
The number of marbles that Mark had at first is repeated. Make the number of marbles that Mark had at first the same. LCM of 6 and 2 is 6.
1 p + 3 u = 58 - 39
1 p + 3 u = 19
1 p = 19 - 3 u --- (1)
1 p + 3 u + 5 u = 39
1 p + 8 u = 39
1 p = 39 - 8 u --- (2)
(1) = (2)
19 - 3 u = 39 - 8 u
8 u - 3 u = 39 - 19
8 u - 3 u = 20
5 u = 20
1 u = 20 ÷ 5 = 4
Substitute 1 u = 4 into (1).
1 p = 19 - 3 u
1 p = 19 - 3 x 4
1 p = 19 - 12
1 p = 7
Number of marbles that Fabian had at first
= 2 p
= 2 x 7
= 14
Answer(s): 14