Oliver, Ethan and Owen had a total of 112 stickers. The ratio of Ethan's stickers to Owen's stickers was 8 : 7 at first. Oliver and Ethan each gave away
12 of their stickers. Given that the three boys had 77 stickers left, how many stickers did Oliver have in the end?
|
Oliver |
Ethan |
Owen |
Total |
Comparing Ethan and Owen at first |
|
8 u |
7 u |
|
Before |
2 p |
2x4 = 8 u |
7 u |
112 |
Change |
- 1 p |
-1x4 = - 4 u |
|
- 35 |
After |
1 p |
1x4 = 4 u |
7 u |
77 |
Total number of stickers that Oliver and Ethan gave away
= 112 - 77
= 35
The number of stickers that Ethan had at first is repeated. Make the number of stickers that Ethan had at first the same. LCM of 8 and 2 is 8.
1 p + 4 u = 112 - 77
1 p + 4 u = 35
1 p = 35 - 4 u --- (1)
1 p + 4 u + 7 u = 77
1 p + 11 u = 77
1 p = 77 - 11 u --- (2)
(1) = (2)
35 - 4 u = 77 - 11 u
11 u - 4 u = 77 - 35
11 u - 4 u = 42
7 u = 42
1 u = 42 ÷ 7 = 6
Substitute 1 u = 6 into (1).
1 p = 35 - 4 u
1 p = 35 - 4 x 6
1 p = 35 - 24
1 p = 11
Number of stickers that Oliver had in the end
= 1 p
= 11
Answer(s): 11