Seth, Ryan and Reggie had a total of 144 cards. The ratio of Ryan's cards to Reggie's cards was 4 : 7 at first. Seth and Ryan each gave away
12 of their cards. Given that the three boys had 114 cards left, how many cards did Seth have in the end?
|
Seth |
Ryan |
Reggie |
Total |
Comparing Ryan and Reggie at first |
|
4 u |
7 u |
|
Before |
2 p |
2x2 = 4 u |
7 u |
144 |
Change |
- 1 p |
-1x2 = - 2 u |
|
- 30 |
After |
1 p |
1x2 = 2 u |
7 u |
114 |
Total number of cards that Seth and Ryan gave away
= 144 - 114
= 30
The number of cards that Ryan had at first is repeated. Make the number of cards that Ryan had at first the same. LCM of 4 and 2 is 4.
1 p + 2 u = 144 - 114
1 p + 2 u = 30
1 p = 30 - 2 u --- (1)
1 p + 2 u + 7 u = 114
1 p + 9 u = 114
1 p = 114 - 9 u --- (2)
(1) = (2)
30 - 2 u = 114 - 9 u
9 u - 2 u = 114 - 30
9 u - 2 u = 84
7 u = 84
1 u = 84 ÷ 7 = 12
Substitute 1 u = 12 into (1).
1 p = 30 - 2 u
1 p = 30 - 2 x 12
1 p = 30 - 24
1 p = 6
Number of cards that Seth had in the end
= 1 p
= 6
Answer(s): 6