Justin, Ivan and Ahmad had a total of 99 stickers. The ratio of Ivan's stickers to Ahmad's stickers was 6 : 5 at first. Justin and Ivan each gave away
12 of their stickers. Given that the three boys had 67 stickers left, how many stickers did Justin have at first?
|
Justin |
Ivan |
Ahmad |
Total |
Comparing Ivan and Ahmad at first |
|
6 u |
5 u |
|
Before |
2 p |
2x3 = 6 u |
5 u |
99 |
Change |
- 1 p |
-1x3 = - 3 u |
|
- 32 |
After |
1 p |
1x3 = 3 u |
5 u |
67 |
Total number of stickers that Justin and Ivan gave away
= 99 - 67
= 32
The number of stickers that Ivan had at first is repeated. Make the number of stickers that Ivan had at first the same. LCM of 6 and 2 is 6.
1 p + 3 u = 99 - 67
1 p + 3 u = 32
1 p = 32 - 3 u --- (1)
1 p + 3 u + 5 u = 67
1 p + 8 u = 67
1 p = 67 - 8 u --- (2)
(1) = (2)
32 - 3 u = 67 - 8 u
8 u - 3 u = 67 - 32
8 u - 3 u = 35
5 u = 35
1 u = 35 ÷ 5 = 7
Substitute 1 u = 7 into (1).
1 p = 32 - 3 u
1 p = 32 - 3 x 7
1 p = 32 - 21
1 p = 11
Number of stickers that Justin had at first
= 2 p
= 2 x 11
= 22
Answer(s): 22