Owen, Paul and David had a total of 51 marbles. The ratio of Paul's marbles to David's marbles was 8 : 5 at first. Owen and Paul each gave away
12 of their marbles. Given that the three boys had 33 marbles left, how many marbles did Owen have at first?
|
Owen |
Paul |
David |
Total |
Comparing Paul and David at first |
|
8 u |
5 u |
|
Before |
2 p |
2x4 = 8 u |
5 u |
51 |
Change |
- 1 p |
-1x4 = - 4 u |
|
- 18 |
After |
1 p |
1x4 = 4 u |
5 u |
33 |
Total number of marbles that Owen and Paul gave away
= 51 - 33
= 18
The number of marbles that Paul had at first is repeated. Make the number of marbles that Paul had at first the same. LCM of 8 and 2 is 8.
1 p + 4 u = 51 - 33
1 p + 4 u = 18
1 p = 18 - 4 u --- (1)
1 p + 4 u + 5 u = 33
1 p + 9 u = 33
1 p = 33 - 9 u --- (2)
(1) = (2)
18 - 4 u = 33 - 9 u
9 u - 4 u = 33 - 18
9 u - 4 u = 15
5 u = 15
1 u = 15 ÷ 5 = 3
Substitute 1 u = 3 into (1).
1 p = 18 - 4 u
1 p = 18 - 4 x 3
1 p = 18 - 12
1 p = 6
Number of marbles that Owen had at first
= 2 p
= 2 x 6
= 12
Answer(s): 12