Roshel spent $54 on some pears, mangoes and chikoos in the ratio of 4 : 2 : 3. The number of pears was
45 the number of mangoes. The ratio of the number of chikoos to the number of mangoes was 3 : 2. The pears were sold at 2 for a dollar.
- How many fruits did she buy altogether?
- How much did each mango cost?
Amount spent |
Pears |
Mangoes |
Chikoos |
Total |
4 u |
2 u |
3 u |
9 u |
Total amount spent on fruits
= 4 u + 2 u + 3 u
= 9 u
9 u = 54
1 u = 54 ÷ 9 = 6
Amount that Roshel spent on pears
= 4 u
= 4 x 6
= $24
Total number of pears that Roshel bought
= 24 x 2
= 48
Number of fruits bought |
Pears |
Mangoes |
Chikoos |
4x2 |
5x2 |
|
|
2x5 |
3x5 |
8 p |
10 p |
15 p |
The number of mangoes bought is repeated. Make the number of mangoes the same. LCM of 2 and 5 is 10.
8 p = 48
1 p = 48 ÷ 8 = 6
Total number of fruits that Roshel bought
= 8 p + 10 p + 15 p
= 33 p
= 33 x 6
= 198
(b)
Total number of mangoes that Roshel bought
= 10 p
= 10 x 6
= 60
Total amount that Roshel paid for the mangoes
= 2 u
= 2 x 6
= $12
Price of each mango
= 12 ÷ 60
= $0.20
Answer(s): (a) 198; (b) $0.20